Line slope calculator 3x-5y=-6
Straight line given by points A[3; 3] and B[8; 6]
Calculation:
Slope: m = 0.6Slope-intercept form of line: y = 0.6x+1.2
Canonical form of the line equation: 3x-5y+6 = 0
Parametric form of the line equation:
x = 5t+3
y = 3t+3 ; t ∈ R
Slope angle of line: φ = 30°57'50″ = 0.5404 rad
X intercept: x0 = -2
Y intercept: y0 = q = 1.2
Distance line from the origin: d0 = 1.029
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; 3)
Normal vector: n = (3; -5)
Midpoint of the segment AB: M = [5.5; 4.5]
Perpendicular Bisector equation: 5x+3y-41 = 0
Vector OA = (3; 3) ; |OA| = 4.2426
Vector OB = (8; 6) ; |OB| = 10
Scalar product OA .OB = 42
Angle ∠ AOB = 8°7'48″ = 0.1419 rad