Line slope calculator 4x+7y=40
Straight line given by points A[3; 4] and B[10; 0]
Calculation:
Slope: m = -0.5714Slope-intercept form of line: y = -0.5714x+5.7143
Canonical form of the line equation: 4x+7y-40 = 0
Parametric form of the line equation:
x = 7t+3
y = -4t+4 ; t ∈ R
Slope angle of line: φ = -29°44'42″ = -0.5191 rad
X intercept: x0 = 10
Y intercept: y0 = q = 5.7143
Distance line from the origin: d0 = 4.9614
The length of the segment AB: |AB| = 8.0623
Vector: AB = (7; -4)
Normal vector: n = (4; 7)
Midpoint of the segment AB: M = [6.5; 2]
Perpendicular Bisector equation: 7x-4y-37.5 = 0
Vector OA = (3; 4) ; |OA| = 5
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 30
Angle ∠ AOB = 53°7'48″ = 0.9273 rad