Line slope calculator x+7y=31


Enter coordinates of two different points:

Straight line given by points A[3; 4] and B[10; 3]

Calculation:

Slope-intercept form of line: y = -0.1429x+4.4286

Canonical form of the line equation: x+7y-31 = 0

Parametric form of the line equation:
x = 7t+3
y = -t+4      ; t ∈ R

Slope: m = -0.1429

Slope angle of line: φ = -8°7'48″ = -0.1419 rad

X intercept: x0 = 31

Y intercept: y0 = q = 4.4286

Distance line from the origin: d0 = 4.3841

The length of the segment AB: |AB| = 7.0711

Vector: AB = (7; -1)

Normal vector: n = (1; 7)

Midpoint of the segment AB: M = [6.5; 3.5]

Perpendicular Bisector equation: 7x-y-42 = 0


Vector OA = (3; 4) ;   |OA| = 5
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 42
Angle ∠ AOB = 36°25'51″ = 0.6358 rad