Line slope calculator x-4y=-13
Straight line given by points A[3; 4] and B[7; 5]
Calculation:
Slope: m = 0.25Slope-intercept form of line: y = 0.25x+3.25
Canonical form of the line equation: x-4y+13 = 0
Parametric form of the line equation:
x = 4t+3
y = t+4 ; t ∈ R
Slope angle of line: φ = 14°2'10″ = 0.245 rad
X intercept: x0 = -13
Y intercept: y0 = q = 3.25
Distance line from the origin: d0 = 3.153
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; 1)
Normal vector: n = (1; -4)
Midpoint of the segment AB: M = [5; 4.5]
Perpendicular Bisector equation: 4x+y-24.5 = 0
Vector OA = (3; 4) ; |OA| = 5
Vector OB = (7; 5) ; |OB| = 8.6023
Scalar product OA .OB = 41
Angle ∠ AOB = 17°35'33″ = 0.307 rad