Line slope calculator 4x+5y=32


Enter coordinates of two different points:

Straight line given by points A[3; 4] and B[8; 0]

Calculation:

Slope-intercept form of line: y = -0.8x+6.4

Canonical form of the line equation: 4x+5y-32 = 0

Parametric form of the line equation:
x = 5t+3
y = -4t+4      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 8

Y intercept: y0 = q = 6.4

Distance line from the origin: d0 = 4.9976

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [5.5; 2]

Perpendicular Bisector equation: 5x-4y-19.5 = 0


Vector OA = (3; 4) ;   |OA| = 5
Vector OB = (8; 0) ;   |OB| = 8
Scalar product OA .OB = 24
Angle ∠ AOB = 53°7'48″ = 0.9273 rad