Line slope calculator 3x+5y=29


Enter coordinates of two different points:

Straight line given by points A[3; 4] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -0.6x+5.8

Canonical form of the line equation: 3x+5y-29 = 0

Parametric form of the line equation:
x = 5t+3
y = -3t+4      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 9.6667

Y intercept: y0 = q = 5.8

Distance line from the origin: d0 = 4.9735

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [5.5; 2.5]

Perpendicular Bisector equation: 5x-3y-20 = 0


Vector OA = (3; 4) ;   |OA| = 5
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 28
Angle ∠ AOB = 46°18″ = 0.8029 rad