Line slope calculator 2x+5y=26


Enter coordinates of two different points:

Straight line given by points A[3; 4] and B[8; 2]

Calculation:

Slope-intercept form of line: y = -0.4x+5.2

Canonical form of the line equation: 2x+5y-26 = 0

Parametric form of the line equation:
x = 5t+3
y = -2t+4      ; t ∈ R

Slope: m = -0.4

Slope angle of line: φ = -21°48'5″ = -0.3805 rad

X intercept: x0 = 13

Y intercept: y0 = q = 5.2

Distance line from the origin: d0 = 4.8281

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; -2)

Normal vector: n = (2; 5)

Midpoint of the segment AB: M = [5.5; 3]

Perpendicular Bisector equation: 5x-2y-21.5 = 0


Vector OA = (3; 4) ;   |OA| = 5
Vector OB = (8; 2) ;   |OB| = 8.2462
Scalar product OA .OB = 32
Angle ∠ AOB = 39°5'38″ = 0.6823 rad