Line slope calculator 2x+5y=26
Straight line given by points A[3; 4] and B[8; 2]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+5.2
Canonical form of the line equation: 2x+5y-26 = 0
Parametric form of the line equation:
x = 5t+3
y = -2t+4 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 13
Y intercept: y0 = q = 5.2
Distance line from the origin: d0 = 4.8281
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [5.5; 3]
Perpendicular Bisector equation: 5x-2y-21.5 = 0
Vector OA = (3; 4) ; |OA| = 5
Vector OB = (8; 2) ; |OB| = 8.2462
Scalar product OA .OB = 32
Angle ∠ AOB = 39°5'38″ = 0.6823 rad