Line slope calculator x+5y=23


Enter coordinates of two different points:

Straight line given by points A[3; 4] and B[8; 3]

Calculation:

Slope-intercept form of line: y = -0.2x+4.6

Canonical form of the line equation: x+5y-23 = 0

Parametric form of the line equation:
x = 5t+3
y = -t+4      ; t ∈ R

Slope: m = -0.2

Slope angle of line: φ = -11°18'36″ = -0.1974 rad

X intercept: x0 = 23

Y intercept: y0 = q = 4.6

Distance line from the origin: d0 = 4.5107

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; -1)

Normal vector: n = (1; 5)

Midpoint of the segment AB: M = [5.5; 3.5]

Perpendicular Bisector equation: 5x-y-24 = 0


Vector OA = (3; 4) ;   |OA| = 5
Vector OB = (8; 3) ;   |OB| = 8.544
Scalar product OA .OB = 36
Angle ∠ AOB = 32°34'27″ = 0.5685 rad