Line slope calculator 4x-5y=-8
Straight line given by points A[3; 4] and B[8; 8]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x+1.6
Canonical form of the line equation: 4x-5y+8 = 0
Parametric form of the line equation:
x = 5t+3
y = 4t+4 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = -2
Y intercept: y0 = q = 1.6
Distance line from the origin: d0 = 1.2494
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [5.5; 6]
Perpendicular Bisector equation: 5x+4y-51.5 = 0
Vector OA = (3; 4) ; |OA| = 5
Vector OB = (8; 8) ; |OB| = 11.3137
Scalar product OA .OB = 56
Angle ∠ AOB = 8°7'48″ = 0.1419 rad