Line slope calculator 2x+y=11


Enter coordinates of two different points:

Straight line given by points A[3; 5] and B[4; 3]

Calculation:

Slope-intercept form of line: y = -2x+11

Canonical form of the line equation: 2x+y-11 = 0

Parametric form of the line equation:
x = t+3
y = -2t+5      ; t ∈ R

Slope: m = -2

Slope angle of line: φ = -63°26'6″ = -1.1071 rad

X intercept: x0 = 5.5

Y intercept: y0 = q = 11

Distance line from the origin: d0 = 4.9193

The length of the segment AB: |AB| = 2.2361

Vector: AB = (1; -2)

Normal vector: n = (2; 1)

Midpoint of the segment AB: M = [3.5; 4]

Perpendicular Bisector equation: x-2y+4.5 = 0


Vector OA = (3; 5) ;   |OA| = 5.831
Vector OB = (4; 3) ;   |OB| = 5
Scalar product OA .OB = 27
Angle ∠ AOB = 22°9'59″ = 0.3869 rad