Line slope calculator 5x+4y=35
Straight line given by points A[3; 5] and B[7; 0]
Calculation:
Slope: m = -1.25Slope-intercept form of line: y = -1.25x+8.75
Canonical form of the line equation: 5x+4y-35 = 0
Parametric form of the line equation:
x = 4t+3
y = -5t+5 ; t ∈ R
Slope angle of line: φ = -51°20'25″ = -0.8961 rad
X intercept: x0 = 7
Y intercept: y0 = q = 8.75
Distance line from the origin: d0 = 5.4661
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; -5)
Normal vector: n = (5; 4)
Midpoint of the segment AB: M = [5; 2.5]
Perpendicular Bisector equation: 4x-5y-7.5 = 0
Vector OA = (3; 5) ; |OA| = 5.831
Vector OB = (7; 0) ; |OB| = 7
Scalar product OA .OB = 21
Angle ∠ AOB = 59°2'10″ = 1.0304 rad