Line slope calculator 5x-4y=-5
Straight line given by points A[3; 5] and B[7; 10]
Calculation:
Slope: m = 1.25Slope-intercept form of line: y = 1.25x+1.25
Canonical form of the line equation: 5x-4y+5 = 0
Parametric form of the line equation:
x = 4t+3
y = 5t+5 ; t ∈ R
Slope angle of line: φ = 51°20'25″ = 0.8961 rad
X intercept: x0 = -1
Y intercept: y0 = q = 1.25
Distance line from the origin: d0 = 0.7809
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; 5)
Normal vector: n = (5; -4)
Midpoint of the segment AB: M = [5; 7.5]
Perpendicular Bisector equation: 4x+5y-57.5 = 0
Vector OA = (3; 5) ; |OA| = 5.831
Vector OB = (7; 10) ; |OB| = 12.2066
Scalar product OA .OB = 71
Angle ∠ AOB = 4°1'42″ = 0.0703 rad