Line slope calculator x+4y=23
Straight line given by points A[3; 5] and B[7; 4]
Calculation:
Slope: m = -0.25Slope-intercept form of line: y = -0.25x+5.75
Canonical form of the line equation: x+4y-23 = 0
Parametric form of the line equation:
x = 4t+3
y = -t+5 ; t ∈ R
Slope angle of line: φ = -14°2'10″ = -0.245 rad
X intercept: x0 = 23
Y intercept: y0 = q = 5.75
Distance line from the origin: d0 = 5.5783
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; -1)
Normal vector: n = (1; 4)
Midpoint of the segment AB: M = [5; 4.5]
Perpendicular Bisector equation: 4x-y-15.5 = 0
Vector OA = (3; 5) ; |OA| = 5.831
Vector OB = (7; 4) ; |OB| = 8.0623
Scalar product OA .OB = 41
Angle ∠ AOB = 29°17'29″ = 0.5112 rad