Line slope calculator 4x+5y=37
Straight line given by points A[3; 5] and B[8; 1]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+7.4
Canonical form of the line equation: 4x+5y-37 = 0
Parametric form of the line equation:
x = 5t+3
y = -4t+5 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 9.25
Y intercept: y0 = q = 7.4
Distance line from the origin: d0 = 5.7784
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [5.5; 3]
Perpendicular Bisector equation: 5x-4y-15.5 = 0
Vector OA = (3; 5) ; |OA| = 5.831
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 29
Angle ∠ AOB = 51°54'40″ = 0.906 rad