Line slope calculator 3x+5y=34
Straight line given by points A[3; 5] and B[8; 2]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+6.8
Canonical form of the line equation: 3x+5y-34 = 0
Parametric form of the line equation:
x = 5t+3
y = -3t+5 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 11.3333
Y intercept: y0 = q = 6.8
Distance line from the origin: d0 = 5.831
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [5.5; 3.5]
Perpendicular Bisector equation: 5x-3y-17 = 0
Vector OA = (3; 5) ; |OA| = 5.831
Vector OB = (8; 2) ; |OB| = 8.2462
Scalar product OA .OB = 34
Angle ∠ AOB = 45° = 0.7854 rad