Line slope calculator 2x+5y=31
Straight line given by points A[3; 5] and B[8; 3]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+6.2
Canonical form of the line equation: 2x+5y-31 = 0
Parametric form of the line equation:
x = 5t+3
y = -2t+5 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 15.5
Y intercept: y0 = q = 6.2
Distance line from the origin: d0 = 5.7566
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [5.5; 4]
Perpendicular Bisector equation: 5x-2y-19.5 = 0
Vector OA = (3; 5) ; |OA| = 5.831
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 39
Angle ∠ AOB = 38°28'49″ = 0.6716 rad