Line slope calculator x-5y=-22
Straight line given by points A[3; 5] and B[8; 6]
Calculation:
Slope: m = 0.2Slope-intercept form of line: y = 0.2x+4.4
Canonical form of the line equation: x-5y+22 = 0
Parametric form of the line equation:
x = 5t+3
y = t+5 ; t ∈ R
Slope angle of line: φ = 11°18'36″ = 0.1974 rad
X intercept: x0 = -22
Y intercept: y0 = q = 4.4
Distance line from the origin: d0 = 4.3146
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; 1)
Normal vector: n = (1; -5)
Midpoint of the segment AB: M = [5.5; 5.5]
Perpendicular Bisector equation: 5x+y-33 = 0
Vector OA = (3; 5) ; |OA| = 5.831
Vector OB = (8; 6) ; |OB| = 10
Scalar product OA .OB = 54
Angle ∠ AOB = 22°9'59″ = 0.3869 rad