Line slope calculator 3x-5y=-16


Enter coordinates of two different points:

Straight line given by points A[3; 5] and B[8; 8]

Calculation:

Slope-intercept form of line: y = 0.6x+3.2

Canonical form of the line equation: 3x-5y+16 = 0

Parametric form of the line equation:
x = 5t+3
y = 3t+5      ; t ∈ R

Slope: m = 0.6

Slope angle of line: φ = 30°57'50″ = 0.5404 rad

X intercept: x0 = -5.3333

Y intercept: y0 = q = 3.2

Distance line from the origin: d0 = 2.744

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; 3)

Normal vector: n = (3; -5)

Midpoint of the segment AB: M = [5.5; 6.5]

Perpendicular Bisector equation: 5x+3y-47 = 0


Vector OA = (3; 5) ;   |OA| = 5.831
Vector OB = (8; 8) ;   |OB| = 11.3137
Scalar product OA .OB = 64
Angle ∠ AOB = 14°2'10″ = 0.245 rad