Line slope calculator 5x-6y=-15
Straight line given by points A[3; 5] and B[9; 10]
Calculation:
Slope: m = 0.8333Slope-intercept form of line: y = 0.8333x+2.5
Canonical form of the line equation: 5x-6y+15 = 0
Parametric form of the line equation:
x = 6t+3
y = 5t+5 ; t ∈ R
Slope angle of line: φ = 39°48'20″ = 0.6947 rad
X intercept: x0 = -3
Y intercept: y0 = q = 2.5
Distance line from the origin: d0 = 1.9206
The length of the segment AB: |AB| = 7.8102
Vector: AB = (6; 5)
Normal vector: n = (5; -6)
Midpoint of the segment AB: M = [6; 7.5]
Perpendicular Bisector equation: 6x+5y-73.5 = 0
Vector OA = (3; 5) ; |OA| = 5.831
Vector OB = (9; 10) ; |OB| = 13.4536
Scalar product OA .OB = 77
Angle ∠ AOB = 11°1'24″ = 0.1924 rad