Line slope calculator x+6y=33


Enter coordinates of two different points:

Straight line given by points A[3; 5] and B[9; 4]

Calculation:

Slope-intercept form of line: y = -0.1667x+5.5

Canonical form of the line equation: x+6y-33 = 0

Parametric form of the line equation:
x = 6t+3
y = -t+5      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 33

Y intercept: y0 = q = 5.5

Distance line from the origin: d0 = 5.4252

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [6; 4.5]

Perpendicular Bisector equation: 6x-y-31.5 = 0


Vector OA = (3; 5) ;   |OA| = 5.831
Vector OB = (9; 4) ;   |OB| = 9.8489
Scalar product OA .OB = 47
Angle ∠ AOB = 35°4'25″ = 0.6122 rad