Line slope calculator 3x+7y=51
Straight line given by points A[3; 6] and B[10; 3]
Calculation:
Slope: m = -0.4286Slope-intercept form of line: y = -0.4286x+7.2857
Canonical form of the line equation: 3x+7y-51 = 0
Parametric form of the line equation:
x = 7t+3
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -23°11'55″ = -0.4049 rad
X intercept: x0 = 17
Y intercept: y0 = q = 7.2857
Distance line from the origin: d0 = 6.6966
The length of the segment AB: |AB| = 7.6158
Vector: AB = (7; -3)
Normal vector: n = (3; 7)
Midpoint of the segment AB: M = [6.5; 4.5]
Perpendicular Bisector equation: 7x-3y-32 = 0
Vector OA = (3; 6) ; |OA| = 6.7082
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 48
Angle ∠ AOB = 46°44'9″ = 0.8157 rad