Line slope calculator 5x+y=21
Straight line given by points A[3; 6] and B[4; 1]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+21
Canonical form of the line equation: 5x+y-21 = 0
Parametric form of the line equation:
x = t+3
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 4.2
Y intercept: y0 = q = 21
Distance line from the origin: d0 = 4.1184
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [3.5; 3.5]
Perpendicular Bisector equation: x-5y+14 = 0
Vector OA = (3; 6) ; |OA| = 6.7082
Vector OB = (4; 1) ; |OB| = 4.1231
Scalar product OA .OB = 18
Angle ∠ AOB = 49°23'55″ = 0.8622 rad