Line slope calculator 3x+y=15
Straight line given by points A[3; 6] and B[4; 3]
Calculation:
Slope: m = -3Slope-intercept form of line: y = -3x+15
Canonical form of the line equation: 3x+y-15 = 0
Parametric form of the line equation:
x = t+3
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -71°33'54″ = -1.249 rad
X intercept: x0 = 5
Y intercept: y0 = q = 15
Distance line from the origin: d0 = 4.7434
The length of the segment AB: |AB| = 3.1623
Vector: AB = (1; -3)
Normal vector: n = (3; 1)
Midpoint of the segment AB: M = [3.5; 4.5]
Perpendicular Bisector equation: x-3y+10 = 0
Vector OA = (3; 6) ; |OA| = 6.7082
Vector OB = (4; 3) ; |OB| = 5
Scalar product OA .OB = 30
Angle ∠ AOB = 26°33'54″ = 0.4636 rad