Line slope calculator x+2y=15
Straight line given by points A[3; 6] and B[5; 5]
Calculation:
Slope: m = -0.5Slope-intercept form of line: y = -0.5x+7.5
Canonical form of the line equation: x+2y-15 = 0
Parametric form of the line equation:
x = 2t+3
y = -t+6 ; t ∈ R
Slope angle of line: φ = -26°33'54″ = -0.4636 rad
X intercept: x0 = 15
Y intercept: y0 = q = 7.5
Distance line from the origin: d0 = 6.7082
The length of the segment AB: |AB| = 2.2361
Vector: AB = (2; -1)
Normal vector: n = (1; 2)
Midpoint of the segment AB: M = [4; 5.5]
Perpendicular Bisector equation: 2x-y-2.5 = 0
Vector OA = (3; 6) ; |OA| = 6.7082
Vector OB = (5; 5) ; |OB| = 7.0711
Scalar product OA .OB = 45
Angle ∠ AOB = 18°26'6″ = 0.3218 rad