Line slope calculator x+2y=15


Enter coordinates of two different points:

Straight line given by points A[3; 6] and B[5; 5]

Calculation:

Slope-intercept form of line: y = -0.5x+7.5

Canonical form of the line equation: x+2y-15 = 0

Parametric form of the line equation:
x = 2t+3
y = -t+6      ; t ∈ R

Slope: m = -0.5

Slope angle of line: φ = -26°33'54″ = -0.4636 rad

X intercept: x0 = 15

Y intercept: y0 = q = 7.5

Distance line from the origin: d0 = 6.7082

The length of the segment AB: |AB| = 2.2361

Vector: AB = (2; -1)

Normal vector: n = (1; 2)

Midpoint of the segment AB: M = [4; 5.5]

Perpendicular Bisector equation: 2x-y-2.5 = 0


Vector OA = (3; 6) ;   |OA| = 6.7082
Vector OB = (5; 5) ;   |OB| = 7.0711
Scalar product OA .OB = 45
Angle ∠ AOB = 18°26'6″ = 0.3218 rad