Line slope calculator 5x+4y=39
Straight line given by points A[3; 6] and B[7; 1]
Calculation:
Slope: m = -1.25Slope-intercept form of line: y = -1.25x+9.75
Canonical form of the line equation: 5x+4y-39 = 0
Parametric form of the line equation:
x = 4t+3
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -51°20'25″ = -0.8961 rad
X intercept: x0 = 7.8
Y intercept: y0 = q = 9.75
Distance line from the origin: d0 = 6.0908
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; -5)
Normal vector: n = (5; 4)
Midpoint of the segment AB: M = [5; 3.5]
Perpendicular Bisector equation: 4x-5y-2.5 = 0
Vector OA = (3; 6) ; |OA| = 6.7082
Vector OB = (7; 1) ; |OB| = 7.0711
Scalar product OA .OB = 27
Angle ∠ AOB = 55°18'17″ = 0.9653 rad