Line slope calculator 5x+4y=39


Enter coordinates of two different points:

Straight line given by points A[3; 6] and B[7; 1]

Calculation:

Slope-intercept form of line: y = -1.25x+9.75

Canonical form of the line equation: 5x+4y-39 = 0

Parametric form of the line equation:
x = 4t+3
y = -5t+6      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 7.8

Y intercept: y0 = q = 9.75

Distance line from the origin: d0 = 6.0908

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [5; 3.5]

Perpendicular Bisector equation: 4x-5y-2.5 = 0


Vector OA = (3; 6) ;   |OA| = 6.7082
Vector OB = (7; 1) ;   |OB| = 7.0711
Scalar product OA .OB = 27
Angle ∠ AOB = 55°18'17″ = 0.9653 rad