Line slope calculator 3x+4y=33


Enter coordinates of two different points:

Straight line given by points A[3; 6] and B[7; 3]

Calculation:

Slope-intercept form of line: y = -0.75x+8.25

Canonical form of the line equation: 3x+4y-33 = 0

Parametric form of the line equation:
x = 4t+3
y = -3t+6      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 11

Y intercept: y0 = q = 8.25

Distance line from the origin: d0 = 6.6

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [5; 4.5]

Perpendicular Bisector equation: 4x-3y-6.5 = 0


Vector OA = (3; 6) ;   |OA| = 6.7082
Vector OB = (7; 3) ;   |OB| = 7.6158
Scalar product OA .OB = 39
Angle ∠ AOB = 40°14'11″ = 0.7023 rad