Line slope calculator 6x+5y=48
Straight line given by points A[3; 6] and B[8; 0]
Calculation:
Slope: m = -1.2Slope-intercept form of line: y = -1.2x+9.6
Canonical form of the line equation: 6x+5y-48 = 0
Parametric form of the line equation:
x = 5t+3
y = -6t+6 ; t ∈ R
Slope angle of line: φ = -50°11'40″ = -0.8761 rad
X intercept: x0 = 8
Y intercept: y0 = q = 9.6
Distance line from the origin: d0 = 6.1458
The length of the segment AB: |AB| = 7.8102
Vector: AB = (5; -6)
Normal vector: n = (6; 5)
Midpoint of the segment AB: M = [5.5; 3]
Perpendicular Bisector equation: 5x-6y-9.5 = 0
Vector OA = (3; 6) ; |OA| = 6.7082
Vector OB = (8; 0) ; |OB| = 8
Scalar product OA .OB = 24
Angle ∠ AOB = 63°26'6″ = 1.1071 rad