Line slope calculator 4x-5y=-18


Enter coordinates of two different points:

Straight line given by points A[3; 6] and B[8; 10]

Calculation:

Slope-intercept form of line: y = 0.8x+3.6

Canonical form of the line equation: 4x-5y+18 = 0

Parametric form of the line equation:
x = 5t+3
y = 4t+6      ; t ∈ R

Slope: m = 0.8

Slope angle of line: φ = 38°39'35″ = 0.6747 rad

X intercept: x0 = -4.5

Y intercept: y0 = q = 3.6

Distance line from the origin: d0 = 2.8111

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; 4)

Normal vector: n = (4; -5)

Midpoint of the segment AB: M = [5.5; 8]

Perpendicular Bisector equation: 5x+4y-59.5 = 0


Vector OA = (3; 6) ;   |OA| = 6.7082
Vector OB = (8; 10) ;   |OB| = 12.8062
Scalar product OA .OB = 84
Angle ∠ AOB = 12°5'41″ = 0.2111 rad