Line slope calculator 4x-5y=-18
Straight line given by points A[3; 6] and B[8; 10]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x+3.6
Canonical form of the line equation: 4x-5y+18 = 0
Parametric form of the line equation:
x = 5t+3
y = 4t+6 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = -4.5
Y intercept: y0 = q = 3.6
Distance line from the origin: d0 = 2.8111
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [5.5; 8]
Perpendicular Bisector equation: 5x+4y-59.5 = 0
Vector OA = (3; 6) ; |OA| = 6.7082
Vector OB = (8; 10) ; |OB| = 12.8062
Scalar product OA .OB = 84
Angle ∠ AOB = 12°5'41″ = 0.2111 rad