Line slope calculator 4x+5y=42


Enter coordinates of two different points:

Straight line given by points A[3; 6] and B[8; 2]

Calculation:

Slope-intercept form of line: y = -0.8x+8.4

Canonical form of the line equation: 4x+5y-42 = 0

Parametric form of the line equation:
x = 5t+3
y = -4t+6      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 10.5

Y intercept: y0 = q = 8.4

Distance line from the origin: d0 = 6.5593

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [5.5; 4]

Perpendicular Bisector equation: 5x-4y-11.5 = 0


Vector OA = (3; 6) ;   |OA| = 6.7082
Vector OB = (8; 2) ;   |OB| = 8.2462
Scalar product OA .OB = 36
Angle ∠ AOB = 49°23'55″ = 0.8622 rad