Line slope calculator 4x+5y=42
Straight line given by points A[3; 6] and B[8; 2]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+8.4
Canonical form of the line equation: 4x+5y-42 = 0
Parametric form of the line equation:
x = 5t+3
y = -4t+6 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 10.5
Y intercept: y0 = q = 8.4
Distance line from the origin: d0 = 6.5593
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [5.5; 4]
Perpendicular Bisector equation: 5x-4y-11.5 = 0
Vector OA = (3; 6) ; |OA| = 6.7082
Vector OB = (8; 2) ; |OB| = 8.2462
Scalar product OA .OB = 36
Angle ∠ AOB = 49°23'55″ = 0.8622 rad