Line slope calculator 3x+5y=39


Enter coordinates of two different points:

Straight line given by points A[3; 6] and B[8; 3]

Calculation:

Slope-intercept form of line: y = -0.6x+7.8

Canonical form of the line equation: 3x+5y-39 = 0

Parametric form of the line equation:
x = 5t+3
y = -3t+6      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 13

Y intercept: y0 = q = 7.8

Distance line from the origin: d0 = 6.6884

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [5.5; 4.5]

Perpendicular Bisector equation: 5x-3y-14 = 0


Vector OA = (3; 6) ;   |OA| = 6.7082
Vector OB = (8; 3) ;   |OB| = 8.544
Scalar product OA .OB = 42
Angle ∠ AOB = 42°52'44″ = 0.7484 rad