Line slope calculator 3x+5y=39
Straight line given by points A[3; 6] and B[8; 3]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+7.8
Canonical form of the line equation: 3x+5y-39 = 0
Parametric form of the line equation:
x = 5t+3
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 13
Y intercept: y0 = q = 7.8
Distance line from the origin: d0 = 6.6884
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [5.5; 4.5]
Perpendicular Bisector equation: 5x-3y-14 = 0
Vector OA = (3; 6) ; |OA| = 6.7082
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 42
Angle ∠ AOB = 42°52'44″ = 0.7484 rad