Line slope calculator 5x+6y=51


Enter coordinates of two different points:

Straight line given by points A[3; 6] and B[9; 1]

Calculation:

Slope-intercept form of line: y = -0.8333x+8.5

Canonical form of the line equation: 5x+6y-51 = 0

Parametric form of the line equation:
x = 6t+3
y = -5t+6      ; t ∈ R

Slope: m = -0.8333

Slope angle of line: φ = -39°48'20″ = -0.6947 rad

X intercept: x0 = 10.2

Y intercept: y0 = q = 8.5

Distance line from the origin: d0 = 6.5299

The length of the segment AB: |AB| = 7.8102

Vector: AB = (6; -5)

Normal vector: n = (5; 6)

Midpoint of the segment AB: M = [6; 3.5]

Perpendicular Bisector equation: 6x-5y-18.5 = 0


Vector OA = (3; 6) ;   |OA| = 6.7082
Vector OB = (9; 1) ;   |OB| = 9.0554
Scalar product OA .OB = 33
Angle ∠ AOB = 57°5'41″ = 0.9965 rad