Line slope calculator x+6y=39
Straight line given by points A[3; 6] and B[9; 5]
Calculation:
Slope: m = -0.1667Slope-intercept form of line: y = -0.1667x+6.5
Canonical form of the line equation: x+6y-39 = 0
Parametric form of the line equation:
x = 6t+3
y = -t+6 ; t ∈ R
Slope angle of line: φ = -9°27'44″ = -0.1651 rad
X intercept: x0 = 39
Y intercept: y0 = q = 6.5
Distance line from the origin: d0 = 6.4116
The length of the segment AB: |AB| = 6.0828
Vector: AB = (6; -1)
Normal vector: n = (1; 6)
Midpoint of the segment AB: M = [6; 5.5]
Perpendicular Bisector equation: 6x-y-30.5 = 0
Vector OA = (3; 6) ; |OA| = 6.7082
Vector OB = (9; 5) ; |OB| = 10.2956
Scalar product OA .OB = 57
Angle ∠ AOB = 34°22'49″ = 0.6001 rad