Line slope calculator x+6y=39


Enter coordinates of two different points:

Straight line given by points A[3; 6] and B[9; 5]

Calculation:

Slope-intercept form of line: y = -0.1667x+6.5

Canonical form of the line equation: x+6y-39 = 0

Parametric form of the line equation:
x = 6t+3
y = -t+6      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 39

Y intercept: y0 = q = 6.5

Distance line from the origin: d0 = 6.4116

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [6; 5.5]

Perpendicular Bisector equation: 6x-y-30.5 = 0


Vector OA = (3; 6) ;   |OA| = 6.7082
Vector OB = (9; 5) ;   |OB| = 10.2956
Scalar product OA .OB = 57
Angle ∠ AOB = 34°22'49″ = 0.6001 rad