Line slope calculator 8x+7y=80
Straight line given by points A[3; 8] and B[10; 0]
Calculation:
Slope: m = -1.1429Slope-intercept form of line: y = -1.1429x+11.4286
Canonical form of the line equation: 8x+7y-80 = 0
Parametric form of the line equation:
x = 7t+3
y = -8t+8 ; t ∈ R
Slope angle of line: φ = -48°48'51″ = -0.852 rad
X intercept: x0 = 10
Y intercept: y0 = q = 11.4286
Distance line from the origin: d0 = 7.5258
The length of the segment AB: |AB| = 10.6301
Vector: AB = (7; -8)
Normal vector: n = (8; 7)
Midpoint of the segment AB: M = [6.5; 4]
Perpendicular Bisector equation: 7x-8y-13.5 = 0
Vector OA = (3; 8) ; |OA| = 8.544
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 30
Angle ∠ AOB = 69°26'38″ = 1.212 rad