Line slope calculator 7x+y=29


Enter coordinates of two different points:

Straight line given by points A[3; 8] and B[4; 1]

Calculation:

Slope-intercept form of line: y = -7x+29

Canonical form of the line equation: 7x+y-29 = 0

Parametric form of the line equation:
x = t+3
y = -7t+8      ; t ∈ R

Slope: m = -7

Slope angle of line: φ = -81°52'12″ = -1.4289 rad

X intercept: x0 = 4.1429

Y intercept: y0 = q = 29

Distance line from the origin: d0 = 4.1012

The length of the segment AB: |AB| = 7.0711

Vector: AB = (1; -7)

Normal vector: n = (7; 1)

Midpoint of the segment AB: M = [3.5; 4.5]

Perpendicular Bisector equation: x-7y+28 = 0


Vector OA = (3; 8) ;   |OA| = 8.544
Vector OB = (4; 1) ;   |OB| = 4.1231
Scalar product OA .OB = 20
Angle ∠ AOB = 55°24'28″ = 0.967 rad