Line slope calculator 4x+y=20


Enter coordinates of two different points:

Straight line given by points A[3; 8] and B[4; 4]

Calculation:

Slope-intercept form of line: y = -4x+20

Canonical form of the line equation: 4x+y-20 = 0

Parametric form of the line equation:
x = t+3
y = -4t+8      ; t ∈ R

Slope: m = -4

Slope angle of line: φ = -75°57'50″ = -1.3258 rad

X intercept: x0 = 5

Y intercept: y0 = q = 20

Distance line from the origin: d0 = 4.8507

The length of the segment AB: |AB| = 4.1231

Vector: AB = (1; -4)

Normal vector: n = (4; 1)

Midpoint of the segment AB: M = [3.5; 6]

Perpendicular Bisector equation: x-4y+20.5 = 0


Vector OA = (3; 8) ;   |OA| = 8.544
Vector OB = (4; 4) ;   |OB| = 5.6569
Scalar product OA .OB = 44
Angle ∠ AOB = 24°26'38″ = 0.4266 rad