Line slope calculator 5x+2y=31


Enter coordinates of two different points:

Straight line given by points A[3; 8] and B[5; 3]

Calculation:

Slope-intercept form of line: y = -2.5x+15.5

Canonical form of the line equation: 5x+2y-31 = 0

Parametric form of the line equation:
x = 2t+3
y = -5t+8      ; t ∈ R

Slope: m = -2.5

Slope angle of line: φ = -68°11'55″ = -1.1903 rad

X intercept: x0 = 6.2

Y intercept: y0 = q = 15.5

Distance line from the origin: d0 = 5.7566

The length of the segment AB: |AB| = 5.3852

Vector: AB = (2; -5)

Normal vector: n = (5; 2)

Midpoint of the segment AB: M = [4; 5.5]

Perpendicular Bisector equation: 2x-5y+19.5 = 0


Vector OA = (3; 8) ;   |OA| = 8.544
Vector OB = (5; 3) ;   |OB| = 5.831
Scalar product OA .OB = 39
Angle ∠ AOB = 38°28'49″ = 0.6716 rad