Line slope calculator 8x+3y=48


Enter coordinates of two different points:

Straight line given by points A[3; 8] and B[6; 0]

Calculation:

Slope-intercept form of line: y = -2.6667x+16

Canonical form of the line equation: 8x+3y-48 = 0

Parametric form of the line equation:
x = 3t+3
y = -8t+8      ; t ∈ R

Slope: m = -2.6667

Slope angle of line: φ = -69°26'38″ = -1.212 rad

X intercept: x0 = 6

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 5.618

The length of the segment AB: |AB| = 8.544

Vector: AB = (3; -8)

Normal vector: n = (8; 3)

Midpoint of the segment AB: M = [4.5; 4]

Perpendicular Bisector equation: 3x-8y+18.5 = 0


Vector OA = (3; 8) ;   |OA| = 8.544
Vector OB = (6; 0) ;   |OB| = 6
Scalar product OA .OB = 18
Angle ∠ AOB = 69°26'38″ = 1.212 rad