Line slope calculator 4x+3y=36


Enter coordinates of two different points:

Straight line given by points A[3; 8] and B[6; 4]

Calculation:

Slope-intercept form of line: y = -1.3333x+12

Canonical form of the line equation: 4x+3y-36 = 0

Parametric form of the line equation:
x = 3t+3
y = -4t+8      ; t ∈ R

Slope: m = -1.3333

Slope angle of line: φ = -53°7'48″ = -0.9273 rad

X intercept: x0 = 9

Y intercept: y0 = q = 12

Distance line from the origin: d0 = 7.2

The length of the segment AB: |AB| = 5

Vector: AB = (3; -4)

Normal vector: n = (4; 3)

Midpoint of the segment AB: M = [4.5; 6]

Perpendicular Bisector equation: 3x-4y+10.5 = 0


Vector OA = (3; 8) ;   |OA| = 8.544
Vector OB = (6; 4) ;   |OB| = 7.2111
Scalar product OA .OB = 50
Angle ∠ AOB = 35°45'14″ = 0.624 rad