Line slope calculator 7x+4y=53
Straight line given by points A[3; 8] and B[7; 1]
Calculation:
Slope: m = -1.75Slope-intercept form of line: y = -1.75x+13.25
Canonical form of the line equation: 7x+4y-53 = 0
Parametric form of the line equation:
x = 4t+3
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -60°15'18″ = -1.0517 rad
X intercept: x0 = 7.5714
Y intercept: y0 = q = 13.25
Distance line from the origin: d0 = 6.5738
The length of the segment AB: |AB| = 8.0623
Vector: AB = (4; -7)
Normal vector: n = (7; 4)
Midpoint of the segment AB: M = [5; 4.5]
Perpendicular Bisector equation: 4x-7y+11.5 = 0
Vector OA = (3; 8) ; |OA| = 8.544
Vector OB = (7; 1) ; |OB| = 7.0711
Scalar product OA .OB = 29
Angle ∠ AOB = 61°18'50″ = 1.0701 rad