Line slope calculator 7x+4y=53


Enter coordinates of two different points:

Straight line given by points A[3; 8] and B[7; 1]

Calculation:

Slope-intercept form of line: y = -1.75x+13.25

Canonical form of the line equation: 7x+4y-53 = 0

Parametric form of the line equation:
x = 4t+3
y = -7t+8      ; t ∈ R

Slope: m = -1.75

Slope angle of line: φ = -60°15'18″ = -1.0517 rad

X intercept: x0 = 7.5714

Y intercept: y0 = q = 13.25

Distance line from the origin: d0 = 6.5738

The length of the segment AB: |AB| = 8.0623

Vector: AB = (4; -7)

Normal vector: n = (7; 4)

Midpoint of the segment AB: M = [5; 4.5]

Perpendicular Bisector equation: 4x-7y+11.5 = 0


Vector OA = (3; 8) ;   |OA| = 8.544
Vector OB = (7; 1) ;   |OB| = 7.0711
Scalar product OA .OB = 29
Angle ∠ AOB = 61°18'50″ = 1.0701 rad