Line slope calculator 2x+4y=38
Straight line given by points A[3; 8] and B[7; 6]
Calculation:
Slope: m = -0.5Slope-intercept form of line: y = -0.5x+9.5
Canonical form of the line equation: 2x+4y-38 = 0
Parametric form of the line equation:
x = 4t+3
y = -2t+8 ; t ∈ R
Slope angle of line: φ = -26°33'54″ = -0.4636 rad
X intercept: x0 = 19
Y intercept: y0 = q = 9.5
Distance line from the origin: d0 = 8.4971
The length of the segment AB: |AB| = 4.4721
Vector: AB = (4; -2)
Normal vector: n = (2; 4)
Midpoint of the segment AB: M = [5; 7]
Perpendicular Bisector equation: 4x-2y-6 = 0
Vector OA = (3; 8) ; |OA| = 8.544
Vector OB = (7; 6) ; |OB| = 9.2195
Scalar product OA .OB = 69
Angle ∠ AOB = 28°50'34″ = 0.5034 rad