Line slope calculator 7x+5y=61
Straight line given by points A[3; 8] and B[8; 1]
Calculation:
Slope: m = -1.4Slope-intercept form of line: y = -1.4x+12.2
Canonical form of the line equation: 7x+5y-61 = 0
Parametric form of the line equation:
x = 5t+3
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -54°27'44″ = -0.9505 rad
X intercept: x0 = 8.7143
Y intercept: y0 = q = 12.2
Distance line from the origin: d0 = 7.0911
The length of the segment AB: |AB| = 8.6023
Vector: AB = (5; -7)
Normal vector: n = (7; 5)
Midpoint of the segment AB: M = [5.5; 4.5]
Perpendicular Bisector equation: 5x-7y+4 = 0
Vector OA = (3; 8) ; |OA| = 8.544
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 32
Angle ∠ AOB = 62°19'8″ = 1.0877 rad