Line slope calculator 4x+5y=52
Straight line given by points A[3; 8] and B[8; 4]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+10.4
Canonical form of the line equation: 4x+5y-52 = 0
Parametric form of the line equation:
x = 5t+3
y = -4t+8 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 13
Y intercept: y0 = q = 10.4
Distance line from the origin: d0 = 8.121
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [5.5; 6]
Perpendicular Bisector equation: 5x-4y-3.5 = 0
Vector OA = (3; 8) ; |OA| = 8.544
Vector OB = (8; 4) ; |OB| = 8.9443
Scalar product OA .OB = 56
Angle ∠ AOB = 42°52'44″ = 0.7484 rad