Line slope calculator 5x+6y=63


Enter coordinates of two different points:

Straight line given by points A[3; 8] and B[9; 3]

Calculation:

Slope-intercept form of line: y = -0.8333x+10.5

Canonical form of the line equation: 5x+6y-63 = 0

Parametric form of the line equation:
x = 6t+3
y = -5t+8      ; t ∈ R

Slope: m = -0.8333

Slope angle of line: φ = -39°48'20″ = -0.6947 rad

X intercept: x0 = 12.6

Y intercept: y0 = q = 10.5

Distance line from the origin: d0 = 8.0663

The length of the segment AB: |AB| = 7.8102

Vector: AB = (6; -5)

Normal vector: n = (5; 6)

Midpoint of the segment AB: M = [6; 5.5]

Perpendicular Bisector equation: 6x-5y-8.5 = 0


Vector OA = (3; 8) ;   |OA| = 8.544
Vector OB = (9; 3) ;   |OB| = 9.4868
Scalar product OA .OB = 51
Angle ∠ AOB = 51°32″ = 0.8903 rad