Line slope calculator 4x-y=16


Enter coordinates of two different points:

Straight line given by points A[4; 0] and B[5; 4]

Calculation:

Slope-intercept form of line: y = 4x-16

Canonical form of the line equation: 4x-y-16 = 0

Parametric form of the line equation:
x = t+4
y = 4t      ; t ∈ R

Slope: m = 4

Slope angle of line: φ = 75°57'50″ = 1.3258 rad

X intercept: x0 = 4

Y intercept: y0 = q = -16

Distance line from the origin: d0 = 3.8806

The length of the segment AB: |AB| = 4.1231

Vector: AB = (1; 4)

Normal vector: n = (4; -1)

Midpoint of the segment AB: M = [4.5; 2]

Perpendicular Bisector equation: x+4y-12.5 = 0


Vector OA = (4; 0) ;   |OA| = 4
Vector OB = (5; 4) ;   |OB| = 6.4031
Scalar product OA .OB = 20
Angle ∠ AOB = 38°39'35″ = 0.6747 rad