Line slope calculator 10x-3y=40


Enter coordinates of two different points:

Straight line given by points A[4; 0] and B[7; 10]

Calculation:

Slope-intercept form of line: y = 3.3333x-13.3333

Canonical form of the line equation: 10x-3y-40 = 0

Parametric form of the line equation:
x = 3t+4
y = 10t      ; t ∈ R

Slope: m = 3.3333

Slope angle of line: φ = 73°18'3″ = 1.2793 rad

X intercept: x0 = 4

Y intercept: y0 = q = -13.3333

Distance line from the origin: d0 = 3.8313

The length of the segment AB: |AB| = 10.4403

Vector: AB = (3; 10)

Normal vector: n = (10; -3)

Midpoint of the segment AB: M = [5.5; 5]

Perpendicular Bisector equation: 3x+10y-66.5 = 0


Vector OA = (4; 0) ;   |OA| = 4
Vector OB = (7; 10) ;   |OB| = 12.2066
Scalar product OA .OB = 28
Angle ∠ AOB = 55°29″ = 0.9601 rad