Line slope calculator 5x-3y=20
Straight line given by points A[4; 0] and B[7; 5]
Calculation:
Slope: m = 1.6667Slope-intercept form of line: y = 1.6667x-6.6667
Canonical form of the line equation: 5x-3y-20 = 0
Parametric form of the line equation:
x = 3t+4
y = 5t ; t ∈ R
Slope angle of line: φ = 59°2'10″ = 1.0304 rad
X intercept: x0 = 4
Y intercept: y0 = q = -6.6667
Distance line from the origin: d0 = 3.43
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; 5)
Normal vector: n = (5; -3)
Midpoint of the segment AB: M = [5.5; 2.5]
Perpendicular Bisector equation: 3x+5y-29 = 0
Vector OA = (4; 0) ; |OA| = 4
Vector OB = (7; 5) ; |OB| = 8.6023
Scalar product OA .OB = 28
Angle ∠ AOB = 35°32'16″ = 0.6202 rad