Line slope calculator 5x-4y=20
Straight line given by points A[4; 0] and B[8; 5]
Calculation:
Slope: m = 1.25Slope-intercept form of line: y = 1.25x-5
Canonical form of the line equation: 5x-4y-20 = 0
Parametric form of the line equation:
x = 4t+4
y = 5t ; t ∈ R
Slope angle of line: φ = 51°20'25″ = 0.8961 rad
X intercept: x0 = 4
Y intercept: y0 = q = -5
Distance line from the origin: d0 = 3.1235
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; 5)
Normal vector: n = (5; -4)
Midpoint of the segment AB: M = [6; 2.5]
Perpendicular Bisector equation: 4x+5y-36.5 = 0
Vector OA = (4; 0) ; |OA| = 4
Vector OB = (8; 5) ; |OB| = 9.434
Scalar product OA .OB = 32
Angle ∠ AOB = 32°19″ = 0.5586 rad