Line slope calculator 4x-5y=16


Enter coordinates of two different points:

Straight line given by points A[4; 0] and B[9; 4]

Calculation:

Slope-intercept form of line: y = 0.8x-3.2

Canonical form of the line equation: 4x-5y-16 = 0

Parametric form of the line equation:
x = 5t+4
y = 4t      ; t ∈ R

Slope: m = 0.8

Slope angle of line: φ = 38°39'35″ = 0.6747 rad

X intercept: x0 = 4

Y intercept: y0 = q = -3.2

Distance line from the origin: d0 = 2.4988

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; 4)

Normal vector: n = (4; -5)

Midpoint of the segment AB: M = [6.5; 2]

Perpendicular Bisector equation: 5x+4y-40.5 = 0


Vector OA = (4; 0) ;   |OA| = 4
Vector OB = (9; 4) ;   |OB| = 9.8489
Scalar product OA .OB = 36
Angle ∠ AOB = 23°57'45″ = 0.4182 rad