Line slope calculator 8x-5y=32


Enter coordinates of two different points:

Straight line given by points A[4; 0] and B[9; 8]

Calculation:

Slope-intercept form of line: y = 1.6x-6.4

Canonical form of the line equation: 8x-5y-32 = 0

Parametric form of the line equation:
x = 5t+4
y = 8t      ; t ∈ R

Slope: m = 1.6

Slope angle of line: φ = 57°59'41″ = 1.0122 rad

X intercept: x0 = 4

Y intercept: y0 = q = -6.4

Distance line from the origin: d0 = 3.392

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; 8)

Normal vector: n = (8; -5)

Midpoint of the segment AB: M = [6.5; 4]

Perpendicular Bisector equation: 5x+8y-64.5 = 0


Vector OA = (4; 0) ;   |OA| = 4
Vector OB = (9; 8) ;   |OB| = 12.0416
Scalar product OA .OB = 36
Angle ∠ AOB = 41°38'1″ = 0.7266 rad