Line slope calculator x+6y=10
Straight line given by points A[4; 1] and B[10; 0]
Calculation:
Slope: m = -0.1667Slope-intercept form of line: y = -0.1667x+1.6667
Canonical form of the line equation: x+6y-10 = 0
Parametric form of the line equation:
x = 6t+4
y = -t+1 ; t ∈ R
Slope angle of line: φ = -9°27'44″ = -0.1651 rad
X intercept: x0 = 10
Y intercept: y0 = q = 1.6667
Distance line from the origin: d0 = 1.644
The length of the segment AB: |AB| = 6.0828
Vector: AB = (6; -1)
Normal vector: n = (1; 6)
Midpoint of the segment AB: M = [7; 0.5]
Perpendicular Bisector equation: 6x-y-41.5 = 0
Vector OA = (4; 1) ; |OA| = 4.1231
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 40
Angle ∠ AOB = 14°2'10″ = 0.245 rad