Line slope calculator x+6y=10


Enter coordinates of two different points:

Straight line given by points A[4; 1] and B[10; 0]

Calculation:

Slope-intercept form of line: y = -0.1667x+1.6667

Canonical form of the line equation: x+6y-10 = 0

Parametric form of the line equation:
x = 6t+4
y = -t+1      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 10

Y intercept: y0 = q = 1.6667

Distance line from the origin: d0 = 1.644

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [7; 0.5]

Perpendicular Bisector equation: 6x-y-41.5 = 0


Vector OA = (4; 1) ;   |OA| = 4.1231
Vector OB = (10; 0) ;   |OB| = 10
Scalar product OA .OB = 40
Angle ∠ AOB = 14°2'10″ = 0.245 rad